Question

A garden hose with a small puncture is stretched horizontally along the ground. The hose is attached to an open water faucet at one end and a closed nozzle at the other end. As you might suspect, water pressure builds up and water squirts vertically out of the puncture to a height of 0.93 m. Determine the pressure inside the hose. (Enter your answer to the nearest 1000 P

Answer 1

Answer:110.439 KPa

Step-by-step explanation:

Given

Height to which water is raised
`h=0.93 m`

assuming
`P_(atm)=101.325 KPa`

Applying Bernoulli's equation between Pipe Puncture and highest Point we get

`P_1+0.5\rho v_1^2+\rho gh_1=P_2+0.5\rho v_2^2+\rho gh_2`

`v_1=0,h_1=0,v_2=0`

we get

`P_1-P_(atm)=\rho gh`

`\Delta P=10^3* 9.8* 0.93`

`P_1=P_(atm)+9.114`

`P_1=101.325+9.114=110.439 KPa`