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Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22. (Past studies have revealed that only 86% of the booked passengers actually arrive for the flight.)Find the probability that if Air-USA books 24 persons, not enough seats will be available.prob =Is this probability low enough so that overbooking problems will be unusual? (Define unusual as having probability 5% or less)A. yes, it is low enoughB. no, it is not low enough

What about defining unusual as 10% or less?A. no, it is not low enoughB. yes, it is low enough

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Answer:

B. no, it is not low enough

A. no, it is not low enough

Explanation:

Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.

Prob for a random person booked arrive for flight = 0.86

No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other

The probability that if Air-USA books 24 persons, not enough seats will be available

= P(X=23)+P(x=24)

= 0.1315

B. no, it is not low enough

-------------------------------

The prob we got is >10% also

A. no, it is not low enough

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