220k views
5 votes
What is the resistance in a light bulb with a voltage of 25V and a current of 0.2A

User Shonna
by
6.8k points

1 Answer

0 votes

Answer:

R = 125Ω

Step-by-step explanation:

Use the equation for voltage:

V = IR

V is voltage, in volts V

I is current, in amperes A

R is resistance, in ohms Ω

Substitute V for 25V and I for 0.2A

V = IR

(25V) = (0.2A)R Isolate R for resistance. Divide both sides by 0.2

R = 125Ω

The resistance for the lightbulb is 125 Ω.

User Ognian Gloushkov
by
5.9k points