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a rectangle with are 315 square inches has a length that is one less than four times the width. find the length and the width of the rectangle ​

User Curieux
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1 Answer

6 votes

Answer:

l=35 inches

w= 9 inches

Explanation:

Area is 315 square inches

Area=l*w=315 (Equation 1)

l=4w-1 (Equation 2)

Putting value of l from equation 2 in equation 1

(4w-1)w=315

4w^2-w-315=0

Solving by using quadratic equation

a=4, b=-1, c=-315

w= (-b+sqrt(b^2-4ac))/2a and w= (-b-sqrt(b^2-4ac))/2a

w= (1+sqrt(1+5040))/8 and w= (1-sqrt(1+5040))/8

w= (1+sqrt(5041))/8 and w= (1-sqrt(5041))/8

sqrt(5041)=71

w= (1+71)/8 and w= (1-71)/8

w=72/8 and w=-70/8

as width can't be a negative number so we'll solve for w=72/8=9

width =9 inches

putting w in equation 2

l=(4*9)-1

l=35 inches

User Swetha Lakshmi
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