Question

A flea jumps by exerting a force of 1.07 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.12 10-6 N on the flea. Find the direction and magnitude (in m/s2) of the acceleration of the flea if its mass is 6.0 10-7 kg. (Let us assume that Fwind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.) magnitude 9.98 m/s2 direction ° (measured clockwise from the vertical)

Answer 1

Step-by-step explanation:

A flea jumps by exerting a force of 1.07 10⁻⁵ N straight down on the ground. It will receive 1.07 x10⁻⁵ N as reaction force which will create an acceleration of a in it so that

1.07x 10⁻⁵ - mg = ma

1.07x 10⁻⁵ - 6 x 10⁻⁷ x 9.8 = 6 x 10⁻⁷ a

48.2 x 10⁻⁷ = 6 x 10⁻⁷ a

a_y = 8 m / s

acceleration in horizontal direction

a_x = 1.12 x 10⁻⁶ / 6 x 10⁻⁷

a_x = 1.12 x 10⁻⁶ / 0.6 x 10⁻⁶

= 1.87 m /s

resultant acceleration

= √(a_x² +a_y²)

= √(1.87² + 8²)

= 8.21 m / s

If angle be θ clockwise from vertical

Tanθ = 1.87 / 8

θ = 13 degree.