Answer:
The maximum efficiency of this thermodynamic engine is η=0.78
Step-by-step explanation:
The maximum efficiency of a thermodynamic engine is consequence of the Maximum Work Theorem, and corresponds to a Carnot Cycle.
The expression is given by
![\eta=1-(T_(c) )/(T_(h) )](https://img.qammunity.org/2020/formulas/physics/college/c6dlc33kmoewyioro6fn8efdtb1zyuhbt2.png)
where
is the temperature of the cold reservoir, and
is the temperature of the hot reservoir, therefore
![\eta=1-(8)/(37)=0.78](https://img.qammunity.org/2020/formulas/physics/college/zapgtrdcc6z3ddgsaarvgk5o0381hcleqv.png)
is the maximum efficiency of this thermodynamic engine.
* It should be noted that a Carnot Cycle is not possible in real engines, it is a theoric tool that allows the development of the thermodynamic engines.