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Sinea thinks that the fully factored form of the expression (x^4-1) is (x^2-1)(x^2+1). Is she correct? Explain.

I NEED THIS ASAP SOMEONE PLEASE HELP!!!

User MSalters
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1 Answer

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Answer:

No. See below.

Explanation:


( {x}^(4) - 1)

Use the following formula (Difference of Two Squares)


{x}^(2) - {y}^(2) = (x + y)(x - y)


( {x}^(4) - 1) = ( {x}^(2) + 1)( {x}^(2) - 1)

We are not done yet. As we can still factor the expression which is x²-1 by using the same formula.


( {x}^(2) + 1)(x + 1)(x - 1)

This is the fully factored form.

User Matthew Arkin
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