Answer:
The length is 10 yards and the width is 20 yards of the playground.
Explanation:
Given,
Area of the rectangular playground = 200 yards.
Solution,
Let the length of the playground be x.
Then the width of the playground is 2x.
Now, According to the formula of area of rectangle;
![Area\ of\ rectangle =length* width](https://img.qammunity.org/2020/formulas/mathematics/high-school/a3lj8crt3n60bncgp5g8q7w3y2ugbvm7jq.png)
On substituting the values, we get;
![x* 2x=200\\\\2x^2=200\\\\x^2=(200)/(2)=100\\\\x^2=100\\\\x=√(100)\\\\x=10\ yards\\](https://img.qammunity.org/2020/formulas/mathematics/high-school/90n9445jfst0igeu6q9mw09vlog9p4slsa.png)
So the length of the playground is 10 yards.
Since the width is twice of the length.
So width =
![2x=2* 10=20\ yards](https://img.qammunity.org/2020/formulas/mathematics/high-school/d3wuuvua19pf17rbqkz080qida3k2h22g5.png)
Hence the length is 10 yards and the width is 20 yards of the playground.