Answer:
Option (C) 24
Explanation:
Let the random variable denoting the amount of gunpowder in the shop be 'x'.
x ~ N(20, 2) i.e. (x-20)/2 ~ (0, 1)
Let 'a' be the amount (in pounds) of gunpowder to stock in inventory.
Thus, P(x<a) = 1 - 0.02 = 0.98
i.e. P[(x-20)/2<(a-20)/2] = 0.98
i.e. ф [(a-2)/2] = 0.98
i.e. (a-20)/2 = ф⁻¹ (0.98) = 2.054
i.e. a = 20 + (2 × 2.054) = 24.108 ≈ 24 pounds
24 pounds of gunpowder to stock in inventory.
Option (C) 24