Height of another tree that cast a shadow which is 20ft long is 5 feet approximately
Solution:
Given that tree with a height of 4 ft casts a shadow 15ft long on the ground
Another tree that cast a shadow which is 20ft long
To find: height of another tree
We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree
![\frac{\text {height of tree}}{\text {length of shadow}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d9o1d0c3yyexvnl0gw41pks6npao10joes.png)
Let us assume,
Height of tree =
![H_t = 4 feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m2quc2qn6fzury8zy1xzmwn58bqyun06dz.png)
Length of shadow of tree =
![L_t = 15 feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9j5qrovii8et9wz3ye0jxjzaog1vm7wc7x.png)
Height of another tree =
![H_a](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5q7q2cnajr7fgszlv4w6m1hfgmr0vl7qkd.png)
Length of shadow of another tree =
![L_a = 20 feet](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r2h8ofhp5ngnx3qaimfmozmn2i63ez3zra.png)
Set up a proportion comparing the height of each object to the length of the shadow,
![\frac{\text {height of tree}}{\text {length of shadow of tree}}=\frac{\text { height of another tree }}{\text { length of shadow of another tree }}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mr5wmz899o6nr3zjaobri1uep8bjd53oay.png)
![(H_(t))/(L_(t))=(H_(a))/(L_(a))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hqo2x3wttsy4w3fods38q7naxn7d6une1b.png)
Substituting the values we get,
![(4)/(15) = (H_a)/(20)\\\\H_a = (4)/(15) * 20\\\\H_a = 5.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gjm1hq51nis454fhiqrmrnmnxc2eh39p28.png)
So the height of another tree is 5 feet approximately