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How to solve 5x + 7y = 1790 and 1x + 1y = 290 algebraically

User Abudayah
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2 Answers

29 votes
29 votes

Answer: x=120; y=170.

Explanation:

1) it is possible to make up the the system of two equations from these two given equations:


\left \{ {{5x+7y=1790} \atop {x+y=290}} \right.

2) the solution of the system above:


\left \{ {{5x+7y=1790} \atop {5x+5y=1450}} \right. \ = > \ \left \{ {{2y=340} \atop {x+y=290}} \right. \ = > \ \left \{ {{y=170} \atop {x=290-y}} \right. \ = > \ \left \{ {{y=170} \atop {x=120}} \right.

3) finally, (120;170).

User Will Hogan
by
3.3k points
25 votes
25 votes

Answer:

Explanation:

How to solve 5x + 7y = 1790 and 1x + 1y = 290 algebraically-example-1
User Djaouad
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2.2k points