Answer:
x=-3, y=-5 & x=1, y=3. The system have two solutions.
Explanation:
x^2+4x-2=2x+1
x^2+4x-2x-2-1=0
x^2+2x-3=0
factor out the trinomial
(x+3)(x-1)=0
zero property
x+3=0, x-1=0
x=0-3=-3
x=0+1=1
y=2(-3)+1=-6+1=-5
y=2(1)+1=2+1=3
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