Question

You perform a single extraction with 100 mL of chloroform to remove compound A from 100 mL of an aqueous solution. The partition coefficient for compound A is 2.5. How much material remains in the aqueous solution after the extraction if you started with 5 g of compound A? Give your answer as a percent.

Answer 1

Percentage of mass of solute in aqueous phase is 28.57%.

Step-by-step explanation:

`(q)_(aq)`- Fraction of solute in aqueous phase.

`(q)_(aq)=(V_(aqueous))/(DV_(organic)+V_(aqueous)))`

`V_(aqueous)` = Used volume of aqueous solution

`V_(organic)` = Used volume of organic solution

D = partition coefficient.

`(q)_(aq)=(100ml)/((2.5*100)+100\,ml)=0.2857`

Mass of solute in aqueous phase =
`0.2857* 5g=1.428g`

`Mass\,percentage = (1.428)/(5.0)* 100=28.57`

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.