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A rectangle has a perimeter of 42 feet. Its length, L, is three feet more than twice its width, W. Create a equation that relates L and W based on the length being three feet more than twice the with

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Answer:

W = 6 feet

L = 15 feet

Explanation:

The perimeter of the rectangle is the length of the outer boundary.

If length is defined as L and width is defined as D,

Perimeter = 2(L + W)

Perimeter is given to be 42 feet.

2(L + W) = 42

(L + W) = 21 ------------------(1)

Also , Its length, L, is three feet more than twice its width, W.

L = 2W + 3 -------------------(2)

Solve (1) and (2) ,

3W + 3 = 21

W = 6 feet

L = 15 feet