Answer:
The time period of the motion is, T = 0.03 s
The frequency of the rotation is, f = 30 Hz
Step-by-step explanation:
Given data,
The rotational speed of an object, ω = 30 rpm
ω = 188.5 rad/s
The time period of motion is,
T = 2π / ω
Substituting the given values in the above equation
= 2π / 188.5
T = 0.03 s
The time period of the motion is, T = 0.03 s
The frequency of rotation,
f = 1 /T
= 1 / 0.03
= 30 Hz
Hence, the frequency of the rotation is, f = 30 Hz