Question

2. A certain object revolves at a rate of 30 rpm. Please determine the frequency and period of this

motion.

Answer 1

The time period of the motion is, T = 0.03 s

The frequency of the rotation is, f = 30 Hz

Step-by-step explanation:

Given data,

The rotational speed of an object, ω = 30 rpm

ω = 188.5 rad/s

The time period of motion is,

T = 2π / ω

Substituting the given values in the above equation

= 2π / 188.5

T = 0.03 s

The time period of the motion is, T = 0.03 s

The frequency of rotation,

f = 1 /T

= 1 / 0.03

= 30 Hz

Hence, the frequency of the rotation is, f = 30 Hz