Question

Camping equipment weighing 6000 N is pulled across a frozen lake by means of a horizontal rope. The coefficient of kinetic friction is 0.05. The work done by the campers in pulling the equipment 1000 m at constant velocity is:

Answer 1

The Work Done is
`3 * 10^5 \ J.`

Step-by-step explanation:

Since , the equipment is pulled in horizontal horizontal plane.

Therefore, its normal reaction must be equal to its weight.

So, Normal reaction,
`N=6000\ N.`

We know, frictional force ,
`F=\mu* N.`

(Where N is Normal reaction and
`\mu` is coefficient of kinetic friction )

Therefore,
`F=0.05 * 6000\ N=300 \ N.`

We know ,

`Work Done , W=F* D`

( Here D is distance covered by the force)

Putting, D=1000 m.

We get , Work Done
`=300* 1000 \ J\\=3* 10^5 \ J.`