Answer:
The three points for the line -2y = -x + 8 are
point A( x₁ , y₁) ≡ ( 0 ,-4)
point B( x₂ , y₂) ≡ (8 , 0)
point C(x₃ , y₃ ) ≡ (2 , -3)
The Graph is attached below.
Explanation:
Given:
-2y = -x + 8........... equation of a line
Let the points be point A, and point B
To Find:
point A( x₁ , y₁) ≡ ?
point B( x₂ , y₂) ≡ ?
point C(x₃ , y₃ ) ≡ ?
Solution:
For Drawing a graph we require minimum two points but we will have here three points.
For point A( x₁ , y₁)
Put x = 0 in the given equation we get
-2y = -x + 8
-2y = 0 + 8
∴
∴ point A( x₁ , y₁) ≡ ( 0 ,-4)
For point B( x₂ , y₂)
Put y= 0 in the given equation we get
-2 × 0 = -x + 8
x = 8
∴ point B( x₂ , y₂) ≡ (8 , 0)
For point C(x₃ , y₃ )
Put x = 2 in the given equation we get
-2y = -2 + 8
-2y = 6
y = - 3
∴ point C(x₃ , y₃ )≡ (2 , -3)
Therefore,
The three points for the line -2y = -x + 8 are
point A( x₁ , y₁) ≡ ( 0 ,-4) (blue color point on the graph)
point B( x₂ , y₂) ≡ (8 , 0) (green color point on the graph)
point C(x₃ , y₃ ) ≡ (2 , -3) (purple color point on the graph)
The Graph is attached below..