Answer:
0.0735,0.0179,0.7026
Explanation:
Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.
Sample size = 49
Population mean = 78
Population std deviation = 28
Std error of sample mean =
![(\sigma)/(√(n) ) \\=4](https://img.qammunity.org/2020/formulas/mathematics/college/f6ibbt4eo0p30zmgyyi2bb27i0wrf6e3re.png)
a)
: N(78, 4)
b)
![P(\bar x >83.8)\\=0.0735](https://img.qammunity.org/2020/formulas/mathematics/college/sw7t56ja3rc4w592fl2aioxpd202lgyvpj.png)
(by converting to Z and finding value from Z table)
c) P (x overbar less than or equals 69.6 )
=
![P(\bar x \leq 69.6)\\=0.0179](https://img.qammunity.org/2020/formulas/mathematics/college/fw36w7x89s3dqqvkhow9klvhj8klh2ywnl.png)
d) P (75.8 less than x overbar less than 88 )
=
![P(75.8<X<88)\\= 0.9938-0.2912\\=0.7026](https://img.qammunity.org/2020/formulas/mathematics/college/hkyck290j265ibqse8670jfvc9s6eu4011.png)