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An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The balloon is then taken outside, where the temperature is . Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly . Be sure your answer has the correct number of significant digits.

User Shaundra
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The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.


V\propto T

or,


(V_1)/(T_1)=(V_2)/(T_2)

where,


V_1 = initial volume of gas = 27.8 L


V_2 = final volume of gas = ?


T_1 = initial temperature of gas =
13^oC=273+13=286K


T_2 = final temperature of gas =
-9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:


(27.8L)/(286K)=(V_2)/(264K)


V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

User Alostale
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