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Balance this chemical equation.

(Baking soda & vinegar)

__NaHCO3 (s) + __HC2H3O2 (aq) = __CO2 (g) + H2O (l) + __NaC2H3O2 (aq)

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User Daar
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2 Answers

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Answer:

get from (4,1) to (2,9) go up 8 and over 2 left (-2) - (4 - 2, 1 + 8), do this again (2 - 2, 9+8) and end up at (0,17) which is the y how do you change 7x+3y=3 into slope intercept form.

get from (4,1) to (2,9) go up 8 and over 2 left (-2) - (4 - 2, 1 + 8), do this again (2 - 2, 9+8) and end up at (0,17) which is the y how do you change 7x+3y=3 into slope intercept form.

get from (4,1) to (2,9) go up 8 and over 2 left (-2) - (4 - 2, 1 + 8), do this again (2 - 2, 9+8) and end up at (0,17) which is the y how do you change 7x+3y=3 into slope intercept form.

get from (4,1) to (2,9) go up 8 and over 2 left (-2) - (4 - 2, 1 + 8), do this again (2 - 2, 9+8) and end up at (0,17) which is the y how do you change 7x+3y=3 into slope intercept form.

get from (4,1) to (2,9) go up 8 and over 2 left (-2) - (4 - 2, 1 + 8), do this again (2 - 2, 9+8) and end up at (0,17) which is the y how do you change 7x+3y=3 into slope intercept form.

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User ATek
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0 votes

Answer:

Step-by-step explanation:

Reaction Given

NaHCO₃ (s) + HC₂H₃O₂ (aq) -------> CO₂ (g) + H₂O (l) + NaC₂H₃O₂ (aq)

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the carbon at the reactant side is 3, the number of carbon must be 3 on the product side.

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

Number of atoms of Reactant:

Na = 1

O = 5

H = 5

C = 3

Number of atoms of Product:

Na = 1

O = 5

H = 5

C = 3

So this a balance equation as the atoms of the reactant atom equal to the number of the product atoms.

Na atom is 1 on both reactant and product side

Oxygen atoms are 5 on reactant and 5 on product side

hydrogen atoms are 5 on reactant and 5 on product side

Carbon atoms are 3 on reactant and 3 on product side

So all the compounds in the reaction have 1 as its coefficient in the blanks

1 NaHCO₃ (s) + 1 HC₂H₃O₂ (aq) -----> 1 CO₂ (g) + 1 H₂O (l) + 1 NaC₂H₃O₂ (aq)

User Twoflower
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