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What is the equation of a line parallel to y=3x+1 that passes through the point at (-2,-4)?

Oy=3x + 4
Dy=3x – 4
y=3x + 2
y= 3x - 2
Pleaseee help!!!

User Udayan
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1 Answer

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Answer:


y=3x+2

Explanation:

Given equation:


y=3x+1

To find the equation of line parallel to the line of the given equation and passes through point (-2,4).

Applying slope relationship between parallel lines.


m_1=m_2

where
m_1 and
m_2 are slopes of parallel lines.

For the given equation in the form
y=mx+b the slope
m_2can be found by comparing
y=3x+1 with standard form.


m_2=3


m_1=3

The line passes through point (-2,4)

Using point slope form:


y_-y_1=m(x_-x_1)

Where
(x_1,y_1)\rightarrow (-2,4) and
m=m_1=3

So,


y-(-4)=3(x-(-2))

Simplifying


y+4=3(x+2)

Using distribution.


y+4=(3x)+(2* 3)


y+4=3x+6

Subtracting 4 from both sides.


y+4-4=3x+6-4


y=3x+2

Thus the equation of line in standard form is given by:


y=3x+2 (Answer)

User Daniel Delaney
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7.6k points