Question

Titanium metal reacts with chlorine gas to form titanium (IV) chloride. What is the theoretical yield for this reaction in grams of titanium (IV) chloride if you start with 5.00 mol of titanium metal and 9.00 mol of chlorine gas?

Answer 1

Answer: The theoretical yield of titanium (IV) chloride is 853.56 grams.

Step-by-step explanation:

We are given:

Moles of titanium metal = 5.00 mole

Moles of chlorine gas = 9.00 mole

The chemical equation for the reaction of titanium and chlorine gas follows:

`Ti+2Cl_2\rightarrow TiCl_4`

By Stoichiometry of the reaction:

2 moles of chlorine gas reacts with 1 mole of titanium metal.

So, 9 moles of chlorine gas will react with =
`(1)/(2)* 9=4.5mol` of titanium metal.

As, given amount of titanium metal is more than the required amount. So, it is considered as an excess reagent.

Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of chlorine gas produces 1 mole of titanium (IV) chloride.

So, 9 moles of chlorine gas will produce =
`(1)/(2)* 9=4.5moles` of titanium (IV) chloride.

To calculate the mass from given number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Molar mass of titanium (IV) chloride = 189.68 g/mol

Moles of titanium (IV) chloride = 4.5 moles

Putting values in above equation, we get:

`4.5mol=\frac{\text{Mass of titanium (IV) chloride}}{189.68g/mol}\\\\\text{Mass of titanium (IV) chloride}=(4.5mol* 189.68g/mol)=853.56g`

Hence, the theoretical yield of titanium (IV) chloride is 853.56 grams.