Question

A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the car experiences a slowing force of 901-N over a distance of 106 m. Determine the speed of the car after traveling this distance.

Answer 1

Final speed, v = 28.81 m/s

Step-by-step explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

`F=ma`

`a=(F)/(m)`

`a=(901)/(1423)`

`a=0.63\ m/s^2`

Let v is the final speed of the car. Using third equation of motion to find it as :

`v^2-u^2=2ad`

`v^2=2ad+u^2`

`v^2=2* 0.63* 106+(26.4)^2`

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.