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A 1.35 ×103 kg car rounds a circular turn of radius 11.9 m. The acceleration of gravity is 9.81 m/s 2 . If the road is flat and the coefficient of static friction between the tires and the road is 0.67, how fast can the car go without skidding? Answer in units of m/s.

User Ymonad
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1 Answer

6 votes

Answer:

velocity = 8.84 m/s

Step-by-step explanation:

given data

radius r = 11.9 m

acceleration of gravity g = 9.81 m/s²

static friction μ = 0.67

to find out

how fast can the car go without skidding

solution

we get here velocity that is car go without skidding is express as

force =
(mv^2)/(r)

force = μ × mg

μ × mg =
(mv^2)/(r)

v² = μ × r × g

v =
√(\mu *r*g) ..................1

v =
√(0.67 *11.9*9.81)

v = 8.84 m/s

velocity = 8.84 m/s

User Mercury Dime
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7.6k points