Question

Electric field just outside a charged conductor is perpendicular to the surface and has a magnitude σ/2ε.

a. True
b. False

Answer 1

The answer is False

Step-by-step explanation:

For a infinite sheet of charges, the electric field is perpendicular to its surface. To calculate the electric field, we use a Gaussian surface (cylinder), getting that

`\Phi=E2A=(\sigma A)/(\epsilon_(0))`

from where

`E=(\sigma)/(2\epsilon_(0))`

Then the field calculated is one half of the field of a conductor charged with
`\sigma`, this means that the magnitude of the charged conductor is

`E=(\sigma)/(\epsilon_(0))`

Therefore the answer is False.