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A male rabbit with genotype GgBb x with a female rabbit with genotype ggbb. Show the punnett square and the excepted offspring and their portions.

User Sandymatt
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2 Answers

3 votes

See attachment below

A male rabbit with genotype GgBb x with a female rabbit with genotype ggbb. Show the-example-1
User Breda
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Answer:

The punnet square is attached as an image.

The expected offsprings have the genotypes GgBb, Ggbb, ggBb and ggbb in the ratio 1:1:1:1 i.e. 4/16 or 1/4 of each offspring will be produced.

Step-by-step explanation:

This a cross involving two genes in rabbits. Gene 1 has two alleles; G and g while the alleles of Gene 2 are B and b.

In a cross between a male rabbit with heterozygous genotype: GgBb and a female rabbit with homozygous genotype: ggbb, each allele will segregate independently of one another into gametes according to Mendel's law of independent assortment. Hence, each parent will produce gametes with the following possible allelic combinations:

GgBb - GB, Gb, gB, gb

ggbb - gb, gb, gb, gb

Using a punnet square (see attached image), 16 possible offsprings will be produced with only four different genotypes: GgBb, Ggbb, ggBb and ggbb in the genotypic ratio 1:1:1:1.

This means that 1/4 of each offsprings' genotype is expected.

A male rabbit with genotype GgBb x with a female rabbit with genotype ggbb. Show the-example-1
User Fennie
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