Answer:
and
![x = -√(17)-5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j6vpvxa363bglohmqwbaa4azfk6ug67hqe.png)
Explanation:
Alright, lets get started.
The given equation is :
![x^(2) +10x = -8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gcwo7ml4xqq6ywlufmgxnfe5x6yk1f3alm.png)
Adding 8 in both sides, it will become
![x^(2) +10x + 8 = -8 +8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sqhldwwxb8f1k9wuxa69nzc3hjiz9g03qs.png)
![x^(2) +10x + 8 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zm212tnfeiqn7c55z0tahyeqcma11fvku0.png)
To make it perfect square, we need to add 25 and subtract 25
![x^(2) +10x + 8 +25-25= 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/toawn2bgk3gqihqca2myle8dka2oeyj5t4.png)
![x^2+10x+25+8-25=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oeovh0pritjid9b25tgdjmlz91jt1mu8g8.png)
![(x+5)^2+8-25=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l95v5drmmdamsvj4v2rb954rh6l8htxww4.png)
![(x+5)^2-17=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bm1sadac97g2hzad8rj2rji1yb4imufz3d.png)
Adding 17 in both sides
taking square root
![x+5=√(17)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nmb77b1ahxbzblyd9ds2wcdw96mtncpduk.png)
So,
and
.. Answer
Hope it will help :)