188k views
5 votes
Given:
m∠LON=77 °
m∠LOM=9x+44 °
m∠MON=6x+3 °

Find ∠MON

User Morrislgn
by
8.7k points

2 Answers

4 votes

Answer:

15

Explanation:

User Vincent Buck
by
7.4k points
1 vote

Answer:


m\angle MON=15^o

Explanation:

see the attached figure to better understand the problem

we know that


m\angle LON=m\angle LOM+m\angle MON ---> by addition angle postulate

substitute the given values


77^o=(9x+44)^o+(6x+3)^o

solve for x


77=(15x+47)


15x=77-47


15x=30\\x=2

Find the measure of angle MON


m\angle MON=(6x+3)^o

substitute the value of x


m\angle MON=(6(2)+3)=15^o

Given: m∠LON=77 ° m∠LOM=9x+44 ° m∠MON=6x+3 ° Find ∠MON-example-1
User Buzzet
by
8.1k points

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