Answer:
Cost of each large soft drink is $3.00 and Cost of each Large bucket of popcorn is $4.50.
Explanation:
Let the Cost of each large soft drink be x.
Also Let the Cost of each Large bucket of popcorn be y.
Number of people = 3
Money Spend on popcorn and soft drink = $22.50
Hence we can say that;
![3x+3y=22.50 \ \ \ \ equation \ 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/qmsamvcksklj4kn3t5lu35imhkmct7dmyo.png)
Next week three people traveled again.
Each ticket was bought = $8.00
Number of tickets bought = 3
Money spend on tickets =
![8*3 = \$24](https://img.qammunity.org/2020/formulas/mathematics/high-school/bxltt3hy4v78qreze8vywoqdss9c9zcp7i.png)
Total return trip = $37.50
Also they each get a large soft drink, but they share one large bucket of popcorn
Cost of Soft drink = 3x
Cost of popcorn = y
Now Total return trip is equal to sum of Money spend on tickets and Cost of soft drink and Cost of popcorn.
Hence equation can be framed as;
![24+3x+y=37.50\\3x+y=37.50-24\\3x+y = 13.50 \ \ \ \ eqaution \ 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/8al3s30t1522fmrj8buhgxw9wwvl7xxhzm.png)
Now Subtracting equation 2 from equation 1 we get;
![(3x+3y)-(3x+y)=22.50-13.50\\\\3x+3y-3x-y=9\\\\2y= 9\\\\y=(9)/(2)=\$4.50](https://img.qammunity.org/2020/formulas/mathematics/high-school/oj4xnt7724ea4qox5t4160aq99m3blzd6l.png)
Now substituting the value of y in equation 1 we get;
![3x+3y=22.50\\\\3x+3*4.50=22.50\\\\3x+13.50=22.50\\\\3x=22.50-13.50\\\\3x= 9\\\\x=(9)/(3)=\$3.00](https://img.qammunity.org/2020/formulas/mathematics/high-school/9jj5evosml3xhnjkcafbvhu8q8dw201fgt.png)
Hence Cost of each large soft drink is $3.00 and Cost of each Large bucket of popcorn is $4.50.