Question

The perimeter of a rectangle is 12. The length is 2 more than the width. Find both dimensions

Answer 1

The dimensions of rectangle as , Length is 4 unit and width is 2 unit

Explanation:

Given as :

The Perimeter of Rectangle = 12 unit

The length is 2 more than the width

Let The Length of Rectangle = L unit

And The width of Rectangle = w unit

According to question

Length = 2 + width

I.e L = 2 + w ...............1

Now, From The Perimeter of Rectangle

Perimeter = 2 × Length + 2 × width

Or, Perimeter = 2 × L + 2 × w

Or, 12 unit = 2 × (2 + w) + 2 × w

Or, 12 = 4 + 2 w + 2 w

or, 12 - 4 = 4 w

Or, 8 = 4 w

∴ w =
`(8)/(4)`

I.e w = 2 unit

So, The width of Rectangle = w = 2 unit

Put The value of w in Eq 1

So, L = 2 + w

I.e L = 2 + 2

∴ L = 4 unit

So, The length of Rectangle = L = 4 unit

Hence The dimensions of rectangle as , Length is 4 unit and width is 2 unit Answer

Answer 2

The dimensions of rectangle are width is 2 and the length is 4.

Explanation:

Given:

The perimeter of a rectangle is 12. The length is 2 more than the width.

Now, to find both the dimensions.

Let the width be
`x`.

And the length be
`2+x`.

Now, putting the formula to get the dimensions:

Perimeter = 2(length + width)

`12=2((2+x)+x)`

⇒
`12=4+2x+2x`

⇒
`12=4+4x`

Subtracting both sides by 4 we get:

⇒
`8=4x`

Dividing both sides by 4 we get:

⇒
`2=x`

So, the width = 2.

And the length = 2+2=4.

Therefore, the dimensions of rectangle are width is 2 and the length is 4.