Answer:
If f(2) = 5, f(3) = 2, f(4) = 5, g(2) = 6, g(3) = 2 and g(4) = 0, find (f · g)(2) 2 +. √. 4 − x2. = 1. 4 . 3. For which value of the constant c is the function f(x) continuous on ? x5 + 6. 5√ x3 , find f (x). Solution. Rewriting f(x) = x. 5. 3 + 6x−3. 5 , we have f (x) = 5. 3 x. 2 x2 − 2x = −1 =⇒ (x − 1)(x − 1)=0=⇒ x = 1. Plugging
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