Question

what temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution (specific heat capacity = 3.5 J/g.c) loses 350 J of heat?

Answer 1

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.

Step-by-step explanation:

Mass of ethylene glycol = m = 100 g

Specific heat capacity of ethylene glycol = c = 3.5 J/g°C

Change in temperature of ethylene glycol = ΔT

Heat loss by the ethylene glycol = Q = 350 J

`Q=mc\Delta T`

`\Delta T=(Q)/(mc)=(350 J)/(100 g* 3.5 J/g^oC)`

ΔT = 1°C

1°C temperature change will be observed if a sample of 100 g of ethylene glycol antifreeze solution.