Question

Please help as fast as you can.

Answer 1

`cos\theta`=
`\sqrt{(85)/(121)}`

`tan\theta`=
`(6)/(√(85))`

Explanation:

given,
`sin\theta`=
`(6)/(11)`

since,
`sin^2\theta`+
`cos^2\theta`=1

`cos^2\theta`=1-
`sin^2theta`

`cos^2\theta[/tax]=1-[tex](36)/(121)`

=
`(121-36)/(121)`

=
`(85)/(121)`

`cos\theta`=
`\sqrt{(85)/(121)}` answer

`tan\theta`=
`(sin\theta)/(cos\theta)`

`tan\theta`=
`(6)/(√(85))` answer