Answer:
The true statements include
- The initial value is 3.
- The range is y >0.
- The simplified base is 8.
Explanation:
f(x) = 3 (16^0.75x) = 3 (16⁰•⁷⁵ˣ)
We will check each of the options for how true they are.
- The initial value is 3.
The initial value of a function is when x=0
and when x=0
f(x) = 3 (16⁰•⁷⁵ˣ)
At x = 0
f(x) = 3 (16⁰) = 3 × 1 = 3.
This statement is true as the the initial value of the function is indeed 3.
- The domain is x>0
The domain of a function refers to the region of values of x where the funcfion exists.
f(x) = 3 (16⁰•⁷⁵ˣ)
It is evident that f(x) will exist any where for any real number value of x. Especially for regions where x ≤ 0, contrary to this statement. Hence, this statement is false.
- The range is y >0.
The range of a function is the set of numbers or region or interval of values that the function can take on.
f(x) = 3 (16⁰•⁷⁵ˣ)
It is evident that this function will always be positive. Hence, the range is truly y>0.
This statement is true.
The last two statements will be solved similarly
f(x) = 3 (16⁰•⁷⁵ˣ)
To simplify This,
f(x) = 3 (2⁴)⁰•⁷⁵ˣ = 3 (2³ˣ) = 3 (8ˣ)
The simplified base is evidently 8.
- The simplified base is 12.
This statement is not evidently true.
- The simplified base is 8.
This statement is true.
Hope this Helps!!!