Question

The population of a small town was 10,800 in 2002. Since then, the population has decreased at a

rate of 2.5% each year. Write an exponential function to model the situation. Select the correction
equation.
A. p=10800(0.975)'
B. p=10800(0.25)'
C. p=1080(0.975)'
D. p=10800(1.025)'​

Answer 1

Explanation:

the answer is 6847 if anyone solves it

Answer 2

The exponential function to model the situation is p = 10800
`(0.975)^(\textrm t)`

Explanation:

Given as :

The population of small town in 2002 = 10,800

The rate of decrease in population = r = 2.5%

Let The number of years of population decrease = t years

Let The population after n years = p

Now, According to question

The population after n years = The population of small town in 2002 ×
`(1-(\textrm rate)/(100))^(\textrm time)`

or, p = 10800 ×
`(1-(\textrm r)/(100))^(\textrm t)`

or, p = 10800 ×
`(1-(\textrm 2.5)/(100))^(\textrm t)`

or, p = 10800 ×
`(0.975)^(\textrm t)`

∴ p = 10800
`(0.975)^(\textrm t)`

Hence, The exponential function to model the situation is p = 10800
`(0.975)^(\textrm t)` . Answer