Question

How do I write an equation of a line that passes through (0,3) and (-5, 2.5)​

Answer 1

y=1/10x+3

Explanation:

m=(y2-y1)/(x2-x1)

m=(2.5-3)/(-5-0)

m=-0.5/-5

m=0.5/5

m=(1/2)/5

m=(1/2)(1/5)

m=1/10

y-y1=m(x-x1)

y-3=1/10(x-0)

y-3=1/10(x)

y-3=1/10x

y=1/10x+3