Question

Molarity of the solution resulting from dissolving 34.9 g of silver nitrate in enough water to give a final volume of 337 mL

Answer 1

Molarity = 0.61 M.

Step-by-step explanation:

atomic mass of AgNO3 = 108 + 14 + 3×16 = 170 g.

therefore number of moles in 34.9 g of AgNO3 =
`(34.9)/(170)`

molarity = (number of moles of solute)/(volume of solution in Litre)

=
`(34.9* 1000)/(170* 337)` = 0.61 M