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Slope of -8,4 and 3,-4

User Deju
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1 Answer

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For this case we have that by definition, the slope of a line is given by:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where:


(x_ {1}, y_ {1})and
(x_ {2}, y_ {2})are two points through which the line passes

According to the statement we have:


(x_ {1}, y_ {1}): (- 8,4)\\(x_ {2}, y_ {2}) :( 3, -4)

Substituting we have:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-4-4} {3 - (- 8)} = \frac {-8} {3 + 8} = \frac {-8} {11} = - \frac {8} {11}

Thus, the slope of the line is:


m = - \frac {8} {11}

Answer:


m = - \frac {8} {11}

User Mishkin
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