Answer:
Explanation:
Given
Restrained Force
![F=116 N](https://img.qammunity.org/2020/formulas/mathematics/high-school/lx7qoxrjqmi51wuzjdj3kcb1yq1r5z6v84.png)
Increase in Kinetic Energy
![\Delta K.E.=30 J](https://img.qammunity.org/2020/formulas/mathematics/high-school/huki122yjb4fwoboftn0pyypsmohecwm6x.png)
Distance moved d=1.9 m
Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force
![\Delta K.E.=W_g+W_f+W_N](https://img.qammunity.org/2020/formulas/mathematics/high-school/9t6btg14geatrr33281uc74ni4x99mg6fn.png)
![30=W_g-F\cdot d](https://img.qammunity.org/2020/formulas/mathematics/high-school/acrwuo5bet12hyh6bl018vfauplci7er2c.png)
![30=W_g-116\cdot 1.9](https://img.qammunity.org/2020/formulas/mathematics/high-school/vs0b72ly62a8b4605ro0cxaj7539yrdtk7.png)
![W_g=250.4 J](https://img.qammunity.org/2020/formulas/mathematics/high-school/m0uw883iu1duj0oj8v98bfzikzk8tjguis.png)
(b)In absence of applied force thus
work done by gravity will be equal to change in kinetic Energy
change in Kinetic Energy
![=210 J](https://img.qammunity.org/2020/formulas/mathematics/high-school/dkjce00484w828ro6swqv69p9h0hj7o844.png)