Question

1. A car having an initial velocity of 12 meters per

second east slows uniformly to 2 meters per
second east in 4.0 seconds. The acceleration of
the car during this 4.0-second interval is

Answer 1

To calculate the acceleration of a car that slows down from 12 m/s to 2 m/s in 4 seconds, use the formula a = (Vf - Vi) / t. The acceleration in this case is -2.5 m/s², indicating deceleration.

Step-by-step explanation:

The student's question is about calculating the acceleration of a car that changes its velocity over a certain time interval. To find the acceleration for the car that slows down uniformly from an initial velocity of 12 meters per second east to 2 meters per second east in 4.0 seconds, we can use the formula a = (Vf - Vi) / t, where a is acceleration, Vf is the final velocity, Vi is the initial velocity, and t is the time interval.

In this case:

Vi = 12 m/s,

Vf = 2 m/s,

t = 4.0 s.

So the acceleration would be:

a = (2 m/s - 12 m/s) / 4.0 s
a = (-10 m/s) / 4.0 s
a = -2.5 m/s²

The negative sign indicates that the car is decelerating, or slowing down.

Answer 2

5/2m/s^2

Step-by-step explanation:

Acceleration is change in velocity divided by change in time. You might have seen it written like this:

ΔV/Δt

in this case, your change in velocity is -10m/s and your change in time is 4s thus your acceleration is -5/2m/s^2