Answer:
(E) 27
Explanation:
Let the 5 digit palindrome be PQRQP
Since each digit is chosen from 1,2,3 therefore
P can either be 1,2 or 3 which gives us 3 options.
Q can also either be 1,2 or 3 which gives us 3 options
R can either be 1,2 or 3 which also gives us 3 options
So we have 3^3 = 3*3*3
= 27
This means 27 palindromes are possible if they are formed using one or more of the digits, 1, 2, 3.