Question

The sum of three numbers is 108. The second number is 4 times the third. The first number is 6 more than the third. What are the numbers?

Answer 1

First number: 13

Second number: 76

Third number: 19

Explanation:

Hope it helps :)

Answer 2

The numbers are 23, 68 and 17.

Explanation:

Given:

The sum of three numbers is 108.

The second number is 4 times the third.

The first number is 6 more than the third.

Now, to find the numbers.

Let the third number be
`x`.

The second number be
`4x`.

And the first number be
`6+x`.

According to question:

`(6+x)+4x+x=108`

Now adding the variables we get:

⇒
`6+6x=108`

Subtracting both sides by 6 we get:

⇒
`6x=102`

Dividing both sides by 6 we get:

⇒
`x=17.`

Third number =
`17.`

Second number =
`4x=4* 17=68.`

First number =
`6+x=6+17=23.`

Therefore, the numbers are 23, 68 and 17.