Question

Write and equation passing through (3, -2) but parallel to y=4x-3

Answer 1

`y=4x-14`

Explanation:

Given:

Point (3, -2)

And line equation is
`y=4x-3`

Compare this equation with
`y=mx+b`

The slope of the required line will be m = 4 and point (3. -2)

Find b by plugging the values of m and the point in below equation

`y=mx+b\\`

Put x and y value from point (3, -2) and slope m value.in above equation.

`-2=4* 3 +b`

`-2=12 +b`

`b=-14`

So, the equation is passing through the point (3, -2) and parallel to
`y=4x-3` is

`y=mx+b`

Put
`m=4` and
`b = -14`

`y=4x-14`

Therefore, equation for the line that passes through (3, -2) and is parallel to the line
`y=4x-3` is

`y=4x-14`