Question

A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specifi heat capacity of the metal

Answer 1

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

`Q=m* c* \Delta T=m* c* (T_(2)-T_(1))`

where,

Q = heat absorbed by metal = 186.75 J

`m_1` = Mass of metal= 19 g

`T_1` = Initial temperature of metal =
`35^oC`

`T_2` =Final temperature of metal =
`175^oC`

`c` = specific heat of metal= ?

`186.75 J=19 g* c* (175^oC-35^oC)`

`c=(186.75 J)/(19 g* (175^oC-35^oC))`

`c=0.0702J/g^oC`

0.0702J/g°C the specific heat capacity of the metal.