Answer:
The volume = 8.94 x 10^25/3.346 x 10^22 =2671.85 mL
Thus, the volume of water added (2671.85 mL) is considerably less than the calculated volume (234000 mL). The pool will not overflow.
Step-by-step explanation:
The volume of water added to the pool can be calculated using the formula below:
Number of molecules (molecules)= N (molecules/mol)*density (g/mL)*volume (mL)/molar mass (g/mol)
Where:
N is the Avogadro constant and it is equal to 6.022 x 10^23, the density of water is 1 g/mL, and molar mass of water is 18 g/mol. In the given problem, 8.94 x 10^25 molecules of water was added, using the formula above:
8.94 x 10^25 = 6.022 x 10^23*1*volume/18
Therefore, volume = 8.94 x 10^25/3.346 x 10^22 =2671.85 mL
Thus, the volume of water added (2671.85 mL) is considerably less than the calculated volume (234000 mL). The pool will not overflow.