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Where on the graph of 2x - 6y = 7 is the x-coordinate twice the y-coordinate?

User Hersson
by
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1 Answer

5 votes

Answer:

The required point is P(-7,
(-7)/(2)) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7

Explanation:

Given equation of line is 2x-6y=7

To find point on graph whose x-coordinate twice the y-coordinate:

Let y be y-coordinate of point

Hence, x-coordinate of point will be 2y

The required point is P(2y,y) on equation of line 2x-6y=7

Now,

2x-6y=7

2(2y)-6y=7

-2y=7

y=
(-7)/(2)

Thus,

The required point is P(-7,
(-7)/(2))

Note: Figure show equation of line red line and point P as blue dot.

Where on the graph of 2x - 6y = 7 is the x-coordinate twice the y-coordinate?-example-1
User Yasmeen
by
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