Question

A frictional force of 78.2 N acts upon a 11.17 kg rightward-moving box to accelerate it leftward. What is the acceleration

Answer 1

`7 m/s^(2)`

Step-by-step explanation:

From the fundamental equation of force

F=ma where F is the applied force, m is the mass of the object and a is the acceleration

Making a the subject of the formula then we obtain

`a=\frac {F}{m}`

Substituting 78.2 N for F and 11.17 Kg for m then we obtain

`a=\frac {78.2}{11.17}=7.000895255\approx 7 m/s^(2)`