Question

A calorimeter has a heat capacity of 1265 J/oC. A reaction causes the temperature of the calorimeter to change from 22.34oC to 25.12oC. How many joules of heat were released in

this process?

Answer 1

heat released is
`3.51 * 10^3 \ J.`

Step-by-step explanation:

It is given that, heat capacity of calorimeter is, H =
`1265 \ J/^0C.`

Also , initial temperature of calorimeter,
`T_i=22.34^0C.`

final temperature of calorimeter,
`T_f=25.12^oC.`

We know , Heat will release when it is positive.

So, heat released , Heat =
`H *(T_f-T_i)=1265*(25.12-22.34)\\=3516.7 \ J=3.51* 10^3\ J.`.

Since it is positive. Therefore, heat released is
`3.51 * 10^3 \ J.`

Answer 2

Heat released in this process is 3516.7 J

Step-by-step explanation:

A calorimeter has a heat capacity of 1265 J/°C

Heat capacity of calorimeter = 1265 J/°C

A reaction causes the temperature of the calorimeter to change from 22.34°C to 25.12°C

Change in temperature = 25.12 - 22.34 = 2.78°C

Heat released = Heat capacity of calorimeter x Change in temperature

Heat released = 1265 x 2.78 = 3516.7 J

Heat released in this process is 3516.7 J