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A hockey player uses a hockey stick to hit a puck such that the stick provides an applied force on the puck. The puck travels for distance of 0.85m while experiencing the force from the stick. The puck leaves the stick with a speed of 8.0m/s and travels at constant speed in a straight line along the horizontal ice for a distance of 12m. The frictional force between the puck and the ice surface is negligible. How does the magnitude of the force exerted by the stick on the puck Fpuck,stick compare to the magnitude of the force exerted by the puck on the stick Fstick,puck at the time interval in which the stick is in contact with the puck?

User Gabriel G
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5.3k points

2 Answers

3 votes

Answer:

Fpuck, stick = Fstick, puck

Explanation:

Because of Newton's third law.

User Aralox
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5.2k points
1 vote

Answer:

Fpuck,stick= Fstick,puck

Explanation:

Force exerted by the stick on the puck is equal to the force exerted by the puck on the stick.

From Newton's third law of motion, we know that action and reaction are equal and opposite.

a force is that which tends to change a body;'s state of rest or uniform motion in a straight line. the impact by the stick on the puck produces an acceleration . on the puck, the impact by the puck on the stick produces an acceleration on the stick although, little.

F1=F2

Notice also that the total momentum before collision is equal to the momentum after collision. The collision is elastic.

User Notedible
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5.5k points
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