Question

Someone solve these equations with working really appreciate it

Answer 1

a)
`t = \sqrt{(d)/(4.9) }`

b) t = 0.3 seconds

c) d = 4.9t²

d) d = 11 cm.

Explanation:

One test involves catching a 1 m ruler and measuring the distance, d in meters, that the ruler will travel before being caught, the reaction time t in seconds is then calculated using the formula

`t = \sqrt{(2d)/(9.8) }` .......... (1)

a) the simplified expression is

`t = \sqrt{(d)/(4.9) }` ......... (2)

b) If d = 44 cm = 0.44 meters, from equation (2) we get,

t = 0.299 seconds ≈ 0.3 seconds (Approximate)

c) If we make d as the subject of the equation, then

`t^(2) = (d)/(4.9)`

⇒ d = 4.9t² .......... (3)

d) Now, if
`t =  (0.3)/(2) = 0.15` seconds, then from equation (3) we get,

d = 4.9 (0.15)² = 0.11 meters = 11 cm (Answer)